Question

b) Given the moment of inertia of a disc of mass M and radius R about any of its
diameters to be MR2/4, find its moment of inertia about an axis normal to the
disc and passing through a point on its edge.​

Answer 1

Answer:

Moment of inertia of disc about its diameter is I

d

=

4

1

MR

2

MI of disc about a tangent passing through rim and in the plane of disc is I=I

G

+MR

2

=

4

1

MR

2

+MR

2

=

4

5

MR

2