Math, asked by mohammedazarudeen776, 4 months ago

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H!
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Example 7: A solid toy is in the form of a
hemisphere surmounted by a right circular cone. The
height of the cone is 2 cm and the diameter of the
Ic С
base is 4 cm. Determine the volume of the toy. If a
right circular cylinder circumscribes the toy, find the
difference of the volumes of the cylinder and the toy.
Р.
(Take t = 3.14)
Solution : Let BPC be the hemisphere and ABC be the cone standing on the base
of the hemisphere (see Fig. 15.14). The radius BO of the hemisphere (as well as
1
of the cone)
x 4 cm 2 cm
2.
2
1
So, volume of the toy
ar +
Fig. 15.14
arh
[ *
3.14(2)+ 3.14% (2)° x 2 cm
25.12 cm
Now, let the right circular cylinder EFGH circumscribe the given solid. The radius of
the base of the right circular cylinder = HP = BO = 2 cm, and its height is
EH AO + OP = (2+2) cm = 4 cm
So, the volume required - volume of the right circular cylinder - volume of the toy
= (3.14 x 22 x 4 -25.12) cm
25.12 cm
Hence, the required difference of the two volumes - 25.12 cm​

Answers

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2

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Answered by 11531112
0

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