Question

बिहार विद्यालय परीक्षा सर्माि M 10 दिये गये पोटैशियम परमैंगनेट घोल की मोलरता M ऑक्नेलिक अम्ल से अनुमापित कर ज्ञात करें। Determine the molarity of the given KMnO4 solution by titrating it against 10 M 10 oxalic acid solution.
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Answer 1

Answer:

KMnO4 acts as an indicator of where the permanganate ions are a deep purple colour. In this redox titration, MnO4– is reduced to colourless manganous ions (Mn2+) in the acidic medium. The last drop of permanganate gives a light pink colour on reaching the endpoint.

Answer 2

Molarity is determined by the formula M₁V₁=M₂V₂

Explanation:

• In the reaction of oxalic acid and potassium permanganate KMnO4 solution, the permanganate ion is a powerful oxidizing agent in an acidic medium.
• In this reaction, oxalic acid and potassium permanganate reacts in an acidic medium.
• The acidic nature is done by adding dilute H₂SO₄
• KMnO₄ acts as a self indicator, where the permanganate ions in KMnO₄  is deep purple colour.