Question

B has two isotopes B10 (19%)&B11(81%). Atomic mass of B is?

Answer 1

((10*19)+(11*81))/100
=( 190+891)/100
= 1081/100
= 10.81

SEE THE ATTACHMENT TOO(ITS TAKEN FROM THE PERIODIC TABLE). its confirms that my calculation is correct.

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Answer 2

this the perfect answer ........

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