Question

b. how much heat is required to convert1g of water at 373 K into steam at 373 K?
(Take Lfusion = 80 cal g-, Lvaporization = 540 cal g- 1)​

Answer 1

Explanation:

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Answer 2

Answer:

540 cal g-¹

Explanation:

water is at 373 k so at this point it change is phase from liquid phase to vapour phase

∆Q=ML

∆Q=1*540= 540 cal g-¹