Computer Science, asked by bhumikaraghu1c, 17 days ago

b. How seek time, latency time, data transfer rate, and access time of magnetic disk is calculated? Explain in detail?

Answers

Answered by Terminator929
0

Answer:

Seek time is the time taken for a hard disk controller to locate a specific piece of stored data. Other delays include transfer time (data rate) and rotational delay (latency). When anything is read or written to a disc drive, the read/write head of the disc needs to move to the right position.

Explanation:

Answered by 28xovenom
0

Answer:

Explanation:

Consider a disk pack with the following specifications- 16 surfaces, 128 tracks per surface, 256 sectors per track and 512 bytes per sector.

Answer the following questions-

What is the capacity of disk pack?

What is the number of bits required to address the sector?

If the format overhead is 32 bytes per sector, what is the formatted disk space?

If the format overhead is 64 bytes per sector, how much amount of memory is lost due to formatting?

If the diameter of innermost track is 21 cm, what is the maximum recording density?

If the diameter of innermost track is 21 cm with 2 KB/cm, what is the capacity of one track?

If the disk is rotating at 3600 RPM, what is the data transfer rate?

If the disk system has rotational speed of 3000 RPM, what is the average access time with a seek time of 11.5 msec?

 

Solution-

 

Given-

Number of surfaces = 16

Number of tracks per surface = 128

Number of sectors per track = 256

Number of bytes per sector = 512 bytes

 

Part-01: Capacity of Disk Pack-

 

Capacity of disk pack

= Total number of surfaces x Number of tracks per surface x Number of sectors per track x Number of bytes per sector

= 16 x 128 x 256 x 512 bytes

= 228 bytes

= 256 MB

 

Part-02: Number of Bits Required To Address Sector-

 

Total number of sectors

= Total number of surfaces x Number of tracks per surface x Number of sectors per track

= 16 x 128 x 256 sectors

= 219 sectors

Thus, Number of bits required to address the sector = 19 bits

 

Part-03: Formatted Disk Space-

 

Formatting overhead

= Total number of sectors x overhead per sector

= 219 x 32 bytes

= 219 x 25 bytes

= 224 bytes

= 16 MB

 

Now, Formatted disk space

= Total disk space – Formatting overhead

= 256 MB – 16 MB

= 240 MB

 

Part-04: Formatting Overhead-

 

Amount of memory lost due to formatting

= Formatting overhead

= Total number of sectors x Overhead per sector

= 219 x 64 bytes

= 219 x 26 bytes

= 225 bytes

= 32 MB

 

Part-05: Maximum Recording Density-

 

Storage capacity of a track

= Number of sectors per track x Number of bytes per sector

= 256 x 512 bytes

= 28 x 29 bytes

= 217 bytes

= 128 KB

 

Circumference of innermost track

= 2 x π x radius

= π x diameter

= 3.14 x 21 cm

= 65.94 cm

 

Now, Maximum recording density

= Recording density of innermost track

= Capacity of a track / Circumference of innermost track

= 128 KB / 65.94 cm

= 1.94 KB/cm

 

Part-06: Capacity Of Track-

 

Circumference of innermost track

= 2 x π x radius

= π x diameter

= 3.14 x 21 cm

= 65.94 cm

 

Capacity of a track

= Storage density of the innermost track x Circumference of the innermost track

= 2 KB/cm x 65.94 cm

= 131.88 KB

≅ 132 KB

 

Part-07: Data Transfer Rate-

 

Number of rotations in one second

= (3600 / 60) rotations/sec

= 60 rotations/sec

 

Now, Data transfer rate

= Number of heads x Capacity of one track x Number of rotations in one second

= 16 x (256 x 512 bytes) x 60

= 24 x 28 x 29 x 60 bytes/sec

= 60 x 221 bytes/sec

= 120 MBps

 

Part-08: Average Access Time-

 

Time taken for one full rotation

= (60 / 3000) sec

= (1 / 50) sec

= 0.02 sec

= 20 msec

 

Average rotational delay

= 1/2 x Time taken for one full rotation

= 1/2 x 20 msec

= 10 msec

 

Now, average access time

= Average seek time + Average rotational delay + Other factors

= 11.5 msec + 10 msec + 0

= 21.5 msec

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