Question

B) Identify me: I am blue in color, have a drop of water in my body. I turn it into
white powder when heated. Guess who I am? What is my molecular formula? please answer send me​

Answer 1

Answer:

the answer is copper sulphate (CuSo4).

Explanation:

hope the answer is helpful to you.

Answer 2

Answer:

Copper sulphate crystals with formula- CuSO₄.5H₂O

Explanation:

• A solution of copper sulphate (CuSO₄.5H₂O) in water is blue due to the d-d transition of ligands (H₂O) around it.

• In CuSO₄.5H₂O, water (H₂O) refers to the water of crystallization.

So as per the question,

• Upon heating, the water present in it gets evaporated and becomes anhydrous.

$CuSO_{4}.5H_{2}O$    →→→→→  $CuSO_{4} + H_{2} O$ ↑

 (blue)     on heating  (white)

• Generally, Salts on heating lose water i.e -after evaporation, change from hydrous to anhydrous salt.

• Thus blue coloured, hydrous copper sulphate salt upon heating changes and gives white-coloured anhydrous copper sulphate salt.

Hence it is identified as Copper sulphate crystals with the formula- CuSO₄.5H₂O