Question

(B) If A = (set of natural numbers less than 20); B = {factors of 18).
C = multiples of 2 less than 30); D = {prime numbers less than 30) then find
(1) A-B (11) A-C (in) A-D (iv) B-C
(UB-D (vi) C-D (vii) C-A (viii) D-B
1969 19 15 = 11.2.3.4.5,6,7,81​

Answer 1

Answer:

A=1,2,3,4...19

B=2,3,6,9,

C=2,4,6,...28

D=2,3,5,7,11,13,17,19,23,29

TOTAL NO. OF

A is 19

B is4

C is 14

D is 10

ATQ

A-B

=19-4

=15

then you can find other question