(b) If p(x) = x2 -2/3x+1, then p(223) is equal to
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Rewrite the polynomial x
2 −1=0 as:x 2 −1=0
⇒x 2 −1 2 =0
⇒(x−1)(x+1)=0(∵a 2 −b 2)
=(a−b)(a+b))
⇒(x−1)=0,(x+1)=0
⇒x=1,x=−1
Hence, the zeroes of the polynomial x 2 −1 are 1,−1.
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the answer for the given question is49574
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