Question

B. If pulleys shown in the diagram are smooth and
massless and a, and a, are acceleration of blocks
of mass 4 kg and 8 kg respectively, then

(Smooth surface)
(1) a1 = a2
(3) 2a1 = a2
(2) a1= 2a2
(4) a1 = 4a2​

Answer 1

$\boxed{\green{\mathsf{Answer}}}$

$a_1= 2a_2$

$\boxed{\green{\mathsf{Explanation}}}$

Given:

$m_1 = 4kg$

$m_2 = 8kg$

To Find:

relation between acceleration of $m_1$ and $m_2$

Solution:-

Let, acceleration of,

• $m_1 \: is \: a_1$
• $m_2 \: is \: a_2$

Now,

Let, Tension is the string attached to

• $m_1$ is T
• $m_</strong><strong>2</strong><strong>$ is 2T

Let us assume that,

"$m_1$ displaces downwards and tension acts upwards"

We know that,

summation of $T.a = 0$

Therefore,

$-T(a_1) + 2T(a_2) = 0$

["-ve" indicates that, tension and acceleration are in opp. direction amd vice versa]

$T(a_1)= 2T(a_2)$

$\cancel{T}(a_1)= 2\cancel{T}(a_2)$

$a_1= 2a_2$_______option (2)

Answer 2

Answer:

hi mate here is your answer ⏬⏬⏬

2 )A1=2a2 is correct answer...

please mark it as brainlist answer ⭐⭐⭐