(b) If x² +y² = 34 and xy =10 ½, find the value of 2(x + y)²+ (x - y)²
Answers
Answered by
61
Solution:
It is given that,
x²+y² = 34 ----(1)
xy = 10½ = 21/2 ---(2)
Value of 2(x+y)²+(x-y)²
= (x+y)² + [(x+y)²+(x-y)²]
= x²+y²+2xy + 2(x²+y²)
= 34 + 2×(21/2)+2×34
= 34 + 21 + 68
= 123
•••
It is given that,
x²+y² = 34 ----(1)
xy = 10½ = 21/2 ---(2)
Value of 2(x+y)²+(x-y)²
= (x+y)² + [(x+y)²+(x-y)²]
= x²+y²+2xy + 2(x²+y²)
= 34 + 2×(21/2)+2×34
= 34 + 21 + 68
= 123
•••
maulikdarji:
ans in text book it is (a)=cube root 20 and (b) = 123
so I am confused
i gave the right answer
he is not able to answer even though he is maths aryabhata
Answered by
36
Answer:
Step-by-step explanation:
x² + y² = 34
(x + y)² - 2xy = 34
(x + y)² - 21 = 34
(x + y)² = 55
The equation :
2 ( 55 ) + (x² + y²) - 2xy
110 + 34 - 21 = 123
but no nedd for that
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