Math, asked by velankyadsouza17, 6 days ago

b) In A PQR, LQ=90 QM ^PR such that (P-M-R).if PM=12cm MR=3 then Qm is ​

Answers

Answered by universalcomputer73
0

Answer:

In ΔPQR, ∠Q = 90° and QM is perpendicular to PR. Prove that: (i) PQ2 = PM × PR (ii) QR2 = PR x MR (iii) PQ2 + QR2 = PR2

Step-by-step explanation:

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