Math, asked by mukeshsharma27, 10 months ago

b. In a right triangle ABC, right angled at C, P and Q
are the points on the sides CA and CB respectively,
which divide these sides in the ratio 1 : 2. Prove that
9(AQ^2 + BP^2) = 10AB^2.​

Answers

Answered by ankitkumarthebest1
1

See the attachment below.

Points to focus PGT

Hope you understand the answer.

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