Question

B. In an equilateral triangleABC,AD perpendicular to BC. then prove that AD^2=3BD^2​

Answer 1

Step-by-step explanation:

Refer to the attachments!!!?

Answer 2

Answer:

PROVED

Step-by-step explanation:

AB = BC = CA

AD is perpendicular to BC so BC is bisected and also ADB is a Pythagorean theorem  so , AD^2 + BD^2 = AB^2

so  BC = BD + CD = BD + BD  = 2BD

AB = BC

AB = 2BD

AD^2 + BD^2 = AB^2

AD^2 + BD^2 = (2BD)^2

AD^2 + BD^2 = 4BD^2

AD^2 = 4BD^2 - BD^2

AD^2 = 3BD^2

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