Question

(b) In each part, from the graph find the value of
y, when (i)x = 2 (ii) x = 3 (iii) x = 0​

Answer 1

Answer:

(i) When x = 2, then A = 4

(ii) When x = 3, then A = 9

(iii) When x = 0 then A = 0.

Step-by-step explanation:

Step : 1 A=$x^2$

giving some values to x, we get corresponding values of y or A

If x = 1, then y or A = $(1)2$=1

If x = 2, then y or A = $(2)2$=4

If x = 0, then or A = $(0)2$=0

x  1  2  0

A  1  4  0

Step : 2  Now plot the point (1, 1), (2, 4), (0, 0) on the graph, and join them to get the graph of A =$x2$ as shown

(b) From the graph we see that

(i) When x = 2, then A = 4

(ii) When x = 3, then A = 9

(iii) When x = 4 then A = 16.

Step : 3 This is due to the fact that the y-intercept occurs when the x value is 0. Y = B when x = 0, since mx = 0 at this point. We set y = 0 and solve the equation for x to determine the x-intercept. Put the value of x into the equation to discover the value of y given the value of x. Think about the formula y = 2x + 6. What does y equal when x equals 5? In the equation, replace the value for x.

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