B
In the adjoining figure, ABCD is a square. A line segment CX cuts AB at X and the diagonal
BD at o such that COD - 80"and ZOXA X". Find the value of x.
80
A
In the adjoin figure, AL and CM are perpendicular to diagonal BD of al gm ABCD. Prove
that (i) AALD ACMB, (ii) AL CM
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Question
In the adjoining figure, ABCD is a square. A line segment CX cuts AB at X and the diagonal BD at O such that ∠ COD = 80° and ∠ OXA = x°. Find the value of x.
Answer x= 55°
Solution
Given
- ABCD is a Square.
- DOC = 80⁰
- DB is a Diagonal.
To Find
- The Value Of x
→ DOX = 180 - COD
→ DOX = 180 - 80⁰
→ DOX= 100⁰
Now In ∆ XOB We have,
- ∠XBO = 45 °. "The diagonals of a square bisect the vertex angle."
- ∠XOB = ∠DOC Vertically Opposite Angle
We know That,
- ∠OXB+∠OBX+∠XOB= 180 ∠angle Sum Property
∠OXB= 180-80-45
- ∠OXB= 55°
Now In the Given Figure
∠x= 180-∠OXB
∠x = 180- 55°
- ∠x = 125°
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