Question

(b) In the figure (ii) given below, ABC is an isosceles right angled triangle with /_ABC = 90°, A semicircle is drawn with AC as diameter. If AB BC = 7 cm,
find the area of the shaded region. Take pie=22÷7​

Answer 1

Answer:

52.5 cm^2

Step-by-step explanation:

AC^2 = AB^2 + BC^2         (using phytagores)

AC^2 = 7^2 + 7^2

AC = √(49 + 49)

AC =  √98 =  7√2 cm

AC is diameter of semi circle

area of shaded region = area of semi circle - area of triangle

pie * (d/2)^2 - 1/2 *AB *AC

22/7 *(7√2/2)^2  - 1/2 *7*7

11*7 - 49 / 2  = (154 - 49) /2 = 105/2 = 52.5 cm^2