Question

(b) In the figure (ii) given below, CD is a diameter which meets the churU AU NI
such that AE = BE = 4 cm. If CE = 3 cm, find the radius of the circle.​

Answer 1

Answer:

Solution :

In △OAM

OA2=OM2+AM2

r2=52+122

r2=169

r=13

In△ONC

OC2=ON2+NC2

NC2=169−144

NC=5

So,

CD=10cm

In△OBE

OB2=OE2+BE2

r2=(r−3)2+42

solving this we get

r=256cm