(b) In the figure (ii) given below, there are five squares each of side 2 cm.
(1) Find the radius of the circle.
(i) Find the area of the shaded region. (Take a = 3:14).
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We have to find
(i) the radius of the circle
(ii) the area of the shaded region.
solution : see figure,
ON = OT + TN = 1 cm + 2 cm = 3 cm
AN = AB/2 = 2cm/2 = 1 cm
From ∆OAN,
OA² = ON² + AN²
⇒OA² = (3cm)² + (1cm)² = 10 cm²
⇒OA = √10 cm
Therefore the radius of the circle is √10 cm.
area of circle = πr² = π(√10 cm)² = 10 × 3.14 cm² = 31.4 cm²
Area of five squares = 5 × area of each square
= 5 × (side length)²
= 5 × (2 cm)²
= 5 × 4 cm²
= 20 cm²
Therefore the area of shaded region = area of circle - area of five squares
= 31.4 cm² - 20 cm²
= 11.4 cm²
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