Question

B. In the given figure, AB || CD and AB = CD. Prove that ∆ABC = ∆CDA.

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Answer 1

Since AB || CD

Angle BAC = Angle ACD...1 (ALTERNATE INTERIOR ANGLE)

Angle DAC = Angle BCA...2 (ALTERNATE INTERIOR ANGLE)

AC = AC (Common)...3

Therefore, triangle ABC = triangle CDA (By ASA criteria)

Answer 2

Step-by-step explanation:

ln a triangle ABD & CDA are Right triangle AC is common side

AB =CD

By RHS axiom

Triangle ABD=TriangleCDA