Question

B
In the given figure, ABCD is a trapezium in which AD || BC,
ZABC = 90°, AD = 16 cm, AC = 41 cm and BC = 40 cm. Find the
area of the trapezium.
Hint. AB2 = (AC2-BC2).
A
16 cm
D
41 cm
The parallel sides of a trapezium are 20
B
40 cm​

Answer 1

Answer:

∠ABC=90°From the right ∆ABC, we have:AB2=(AC2−BC2)⇒AB2={(412)−(402)}⇒AB2=(1681−1600)⇒AB2=81⇒AB=81−−√⇒AB=9 cm∴ Length AB=9 cmNow,Area of the trapezium={12×(AD+BC)×AB}

=(12×(16+40)×9) cm2=(12×56×9) cm2=(28×9) cm2=252 cm2