Question

B is 200% efficent than A and 50% efficient than C, if all if them work together for 2 days to complete the work, then in how many days a alone can complete the work?

Answer 1

let A capacity = x work per day

as B is 200% efficient, (B capacity - A capacity)/A capacity*100 =200

solving the above will give B capacity= 3x

same way (B capacity - C capacity)/C capacity*100 =50

solving above will give C capacity= 2x

so in one day total work done by A, B, C is x+2x+3x=6x

in two days = 12x

so a alone will complete work of 12x in 12x/x = 12 days.