Math, asked by TheRealSardar4150, 11 months ago

B is 22 year older than c, while c is 16 year younger than A. The ratio of the age C four year hence and age of B nine year ago is 4:5. Then what is the age of A

Answers

Answered by VishnuPriya2801
8

Answer:

48 years.

Step-by-step explanation:

Let the age of A be "x".

given,

C's age = (x - 16) years.

B 's age = x - 16 + 22

B's age = x + 6

Four years after, C's age = x - 16 + 4

C's age = x - 12

Nine years ago, B's age = x + 6 - 9

B's age = x - 3

given,

Ratio = 4/5

C/B = 4/5

x - 12/x - 3 = 4/5

After cross multiplication we get,

5(x - 12) = 4(x - 3)

5x - 60 = 4x - 12

5x - 4x = -12 + 60

x = 48 years.

Therefore, A's age is 48 years.

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