Math, asked by buttercup797, 1 day ago

B is 50% more efficient than A. C's efficiency is 75% of A's efficiency. B and C working together can complete a piece of work in 24 days, then find in how many days A,B & C working together will complete the same work, if A and B are working with 50% increased efficiency.


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Answers

Answered by Anonymous
2

\huge\green{{ ❥︎ Question}}

➪ B is 50% more efficient than A. C's efficiency is 75% of A's efficiency. B and C working together can complete a piece of work in 24 days, then find in how many days A,B & C working together will complete the same work, if A and B are working with 50% increased efficiency.

\huge\green{{ ❥︎ Answer}}

let \: the \: total \: wrk \:  = 1 \: part

in \: 24days \: a  \: can \: do \: 1part \: work

in \: day \: a \: can \: do \:  \frac{1}{24} part \: of \: the \: work

as \: b \: is \: 50\% \: more \: eficent \: than \: a \: so

in \: 1 \: day \: b \: can \: do \:

{( \frac{1}{24}  + ( \frac{1}{24})} \:  \frac{50}{100} part \: of \: work \:

= (2+1)/48 part of work = 1/16 part of work

☞Therefore, B can do 1/16 part of work in 1 day

☞Therefore B can do 1 part of work in 1*16/1 day

☞Therefore B can complete the work in 16 days.ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

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Answered by mariya57
2

Answer:

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