Question

B is 8 years elder to A.C is 12 years younger to A.If 8 years hence age of A is is 1.5 times the average age of B and C two years back then what will be the age of A after 2 years.

Answer 1

B= A+8.
C = A - 12
According to the given question.

A + 8 = 3/2 * ( B+C / 2)
A + 8 = 3/2* ( A+8+A-12 / 2)
A+8 = 3( 2A -4)/4
4A+32 = 6A - 12
2A = 44
A = 22 years = Present age of A

So the age of A after two years will be 22+2 = 24 years

Answer 2

Present age of A= 22years
After two years age of A will be 22+2=24 years