B is 8 years elder to A.C is 12 years younger to A.If 8 years hence age of A is 1.5 times the average age of B and C two years back then what will be the age of A after two years?
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B= A+8.
C = A - 12
According to the given question.
A + 8 = 3/2 * ( B+C / 2) - 2
A + 8 = 3/2* ( A+8+A-12 / 2)-2
A+8 = 3/2 ( 2A - 4 - 4 / 2)
A+8 = 3/4* 2A - 8
4A + 32 = 6A - 24
2A = 56
A = 28 years
A = 28 years = Present age of A
So the age of A after two years will be 28+2 = 30 years
Hope this helps. ....
C = A - 12
According to the given question.
A + 8 = 3/2 * ( B+C / 2) - 2
A + 8 = 3/2* ( A+8+A-12 / 2)-2
A+8 = 3/2 ( 2A - 4 - 4 / 2)
A+8 = 3/4* 2A - 8
4A + 32 = 6A - 24
2A = 56
A = 28 years
A = 28 years = Present age of A
So the age of A after two years will be 28+2 = 30 years
Hope this helps. ....
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