B is elder to A by 4 years. Five years ago, the age of B was 9 years. What the sum of their ages after five years
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Answered by
1
B is elder to A = B- A =4
Five years ago
B=9 then A= B-4(from the above equation) = 9-4= 5
Five years later from then (present)
B=14. A= 10
Five years later from present
B=19 A= 15
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Answered by
0
B= A + 4
five years ago
age of B = B - 5 = 9
age of A= A - 5
B - 5 = 9
B= 14 years
14= A + 4
A = 14 - 4
A = 10 years
five years ago
age of B = B - 5 = 9
age of A= A - 5
B - 5 = 9
B= 14 years
14= A + 4
A = 14 - 4
A = 10 years
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