Question

b) Length of a rectangle is 5 cm more than twice of its breadth.
If area of the rectangle is 1950 sq.cm, then find the perimeter
of rectangle.​

Answer 1

Hey mate here's your answer..

Hope you understood then mark as BRAINLIST plz..

Answer 2

$\huge{\underline{\underline{\pink{\mathcal{Solution}}}}}:-$

Let the breadth of the rectangle be b.

then,the length of rectangle will be = 5 + 2b

$\boxed{Area\; of \;rectangle \;= length × Breadth}$

So, 5 + 2b (b) = 1950

= 5b + 2b² = 1950

= 2b² + 5b - 1950

Here, a = 2 , b = 5, c = -1950 and D = 25

Now using Formula:-

$x = \frac{-b + \sqrt{D}}{2a}$

Putting values :-

$\rightarrow x = \frac{ -5+ \sqrt{20}}{4}$

$\rightarrow x = \frac{-5 + 625}{4}$

$\rightarrow x = \frac{ -5 + 125}{4}$

$\rightarrow x = \frac{-5 - 125}{4}$

Breadth = 30 cm

Length = 5 + 2(30)

Length = 5 + 60

Length = 65 cm

Finding perimeter of rectangle =

2( length + Breadth)

$\implies 2(65 + 30)$

$\implies 2(95)$

$\implies 195cm$

$\boxed{Perimeter \;of\; rectangle\; = 195\; sq. units}$

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