Question

b)MnO- + I- = MnO 2 + I2 ​

Answer 1

Answer:

The unbalanced chemical equation is

MnO

4

−

(aq)+I

−

(aq)→MnO

2

(s)+I

2

(s)

The oxidation half reaction is

I

−

(aq)→I

2

(s)

The reduction half reaction is

MnO

4

−

(aq)→MnO

2

(aq)

Balance I atoms and charges in the oxidation half reaction.

2I

−

(aq)→I

2

(s)+2e

−

In the reduction half reaction, the oxidation number of Mn changes from +7 to +4. Hence, add 3 electrons to reactant side of the reaction.

MnO

4

−

(aq)+3e

−

→MnO

2

(aq)

Balance charge in the reduction half reaction by adding 4 hydroxide

ions to product side.

MnO

4

−

(aq)+3e

−

→MnO

2

(aq)+4OH

−

To balance O atoms, add 2 water molecules to reactant side.

MnO

4

−

(aq)+3e

−

+2H

2

O→MnO

2

(aq)+4OH

−

To equalize the number of electrons, multiply the oxidation half reaction by 3 and multiply the reduction half reaction by 2.

6I

−

(aq)→3I

2

(s)+6e

−

2MnO

4

−

(aq)+6e

−

+4H

2

O→2MnO

2

(aq)+8OH

−

Add two half cell reactions to obtain the balanced equation.

2MnO

4

−

(aq)+6I

−

(aq)+4H

2

O

2

(l)→2MnO

2

(s)+3I

2

(s)+8OH

−

Mark me as brainliest