Question

बिन्दु (8,-6)की मूल बिन्दु से दूरी है ।​

Answer 1

Answer:

$distance \: between \: (0.0) \: and \: (8.0 )= 8u \\ distance \: between \: (8.0) \: and \: (8. - 6) = 6u \\ distance \: between \: (0.0) \: and \: (8. - 6) = xu \\ \: by \: pythagoras \: theorem \\ {hypotenuse}^{2} = {perpendicular }^{2} + {base}^{2} \\ {x}^{2} = {8}^{2} + {6}^{2} \\ {x}^{2} = 64 + 36 \\ {x}^{2} = 100 \\ x = \sqrt{100} \\ x = 10u$

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