Question

बिन्दुओ a(2;-3) तथा b(x;5) के बीच की दूरी 10 इकाई है तो a=?

Answer 1

Answer:

(2-x)²+(-3-5)² = 10²

4+x²-4x +64 = 100

x²-4x -32 = 0

x²-8x+4x-32 = 0

x(x-8)+4(x-8) = 0

(x-8)(x+4) = 0

x = 8 & -4 (Ans)

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Answer 2

Explanation:

(2-x)²+(-3-5)² = 10²

4+x²-4x +64 = 100

x²-4x -32 = 0

x²-8x+4x-32 = 0

x(x-8)+4(x-8) = 0

(x-8)(x+4) = 0

x = 8 & -4 (Ans)