B of 0.4M aqueous solution of KOH is mixed with 4L of 1.0M aqueous solution ot KOH. The molarity of the resulting solution is..
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0.4 moles of B present in 1litre of 1st Solution KOH
4 moles of B present in 4 litre of 2nd solution of KOH
Molarity = total moles / total volume = 4.4/5 = 0.8M
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