Chemistry, asked by zamanatrizvi5, 2 months ago

(b) On dissolving 1.17 gm of cane sugar in 25 gm of water, the boiling
point of solvent is increased by 0.017°C.What will be the molar elevatin
constant of the solvent? (Molecular weight of cane sugar=342).

Answers

Answered by yashkumarmahto1871

0

Answer:

KshswibvwejjeehfejenIbd68:0838 8_858, 6=8=5 3&75&3₹88=36

Explanation:

(53 368')8₹8+()(5856#9.)% 8(6)6,)5/" 3 in a

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