Math, asked by chaudhary1753, 9 months ago

b) p(x)=(x-1)(x+1),p(0),p(1),p(2)

Answers

Answered by 9435034093sonu
1

Step-by-step explanation:

p(0) = (0-1)(0+1) = (-1)1 = -1

p(1) = (1-1)(1+1) = 0(2) = 0

p(2) = (2-1)(2+1) = (1)(3) = 3

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Answered by snehaPranathi
1

Answer:

p (0) = (0-1)(0+1)= -1

p (1) = (1-1)(1+1)=0

p (2) = (2-1)(2+1) = 3.

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