Question

b part pls pls pls pls pls pls​

Answer 1

Step-by-step explanation:

In one revolution it will cover the distance equal to its circumference(2πr). So in 5 revolutions distance covered = 5 × 2πr

r = 35 cm = 0.35 m (because 100 cm = 1 m)

Distance covered in 5 revolutions

=5× 2πr

=5×2×(22/7) × 0.35

=10×0.35×(22/7)

=3.5×(22/7)

=0.5×22

=11 metres

Answer 2

Answer:

Given Information:-

• Radius of the wheel : 35 cms

To Find:-

1. Circumference (/perimeter) of the wheel.
2. Distance covered in 5 revolutions in metres.

____________...

Circumference:-

$\boxed{\large\tt{2 \pi r}}$

(where,

$\tt{\pi = \frac {22}{7}}$ )

Hence, let's jump into the first number!

(a)

As radius is 35 cm,

Hence, it's circumference will be:-

$\tt{2 \pi r}$

(Circumference of circle formulae)

$\tt{=2 \times \frac {22}{7} \times 35 \ cm}$

(Written the value of pi along with radius)

$\tt{= 2 \times \frac {22}{\cancel{7}} \times {\cancel{35}} \ cm}$

(Cancelled 35 and 7 with taking common of 7)

$\tt{= 2 \times 22 \times 5 \ cm}$

(Value after cancellation)

$\tt{= 22 \times 10 \ cm}$

(Multiplied 5 with 2)

$\tt\purple{= 220 \ cm}$

(Multiplied 22 and 10 and hence, circumference found!)

____________...

NOW, Second!!

(b) Since, one revolution takes 220 cm, hence, 5 revolutions will take:-

$\tt{\frac {220 \times 5}{100} \ cm}$

(Suitable expression as we have to find in metres)

$\tt{= \frac {1100}{100} \ cm}$

(Multiplied the. nominators)

$\tt\purple{= 11 \ m}$

(Answer of the second question!)

____________...

REQUIRED ANSWER:-

$\tt{\therefore}$ Circumference of the wheel is $\boxed{\large\tt{220 \ cm}}$ and distance covered after 5 revolutions is $\boxed{\large\tt{11 \ m}}$.