Math, asked by sunita4831, 11 months ago

B part plzz fast.....​

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Answered by zakirhussain786
1

Answer:

Given:

Radius of the lower end of the container(r) = 20 cm Radius of the bigger end of the container( R) = 40 cm Height of the container(h) = 30 cm Capacity of container = 1/3th[R² + r²+ Rr]

=1/3x22/7x30x[(40)²+(20)²+40x20]

=1/3x22/7x30x[1600 +400 +800] =1/3x22/7x30x[2800] =22x10x[400] =88000 cm³

= 88000/1000

=88 litres [1000 cm = 1 litres]

Amount of milk needed by the camp daily = 880 litres Hence, number of containers needed =880/88 = 10

cost of 1 litre milk = Rs 35

Cost of 880 litres of milk = (35 x 880) => 30800 rupees

HOPE THIS WILL HELP YOU...

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