Question

(b) Potassium bicarbonate + sulphuric acid → potassium sulphate + carbon dioxide + water write balanced chemical equation ​

Answer 1

Answer:

2KHCO3 + H2SO4 = K2SO4 + 2CO2 + 2H2O

Potassium hydrogen carbonate reacts with dilute sulphuric acid to form potassium sulphate, carbon dioxide and water

Answer 2

THE BALANCED CHEMICAL EQUATION FOR "Potassium bicarbonate + sulphuric acid → potassium sulphate + carbon dioxide + water" WILL BE

$2KHCO_{3} +H_{2} SO_{4} ---> K_{2} SO_{4} +2CO_{2}+2H_{2} O$

Explanation:

• The chemical equations are balanced to follow the law of conservation of mass.
• It states that mass is neither created nor destroyed during a chemical reaction. So, the number of atoms reacting must be equal to number of atoms being formed.
• The equation given in question can be written as:

       $KHCO_{3} +H_{2} SO_{4} ---> K_{2} SO_{4} +CO_{2}+H_{2} O$

• First we look for an atom which has maximum difference in its number, potassium and hydrogen differ by one.
• We will multiply potassium bicarbonate by 2.

        $2KHCO_{3} +H_{2} SO_{4} ---> K_{2} SO_{4} +CO_{2}+H_{2} O$

• Now we will multiply carbon dioxide and water by 2 to balance both the reactant and product side atoms.

       $2KHCO_{3} +H_{2} SO_{4} ---> K_{2} SO_{4} +2CO_{2}+2H_{2} O$