Question

b) Propanal and pentan-3-one are the ozonolysis products of an alkene.
Write the structural formula of the alkene and give its IUPAC name.​

Answer 1

✪ Answer ✪

Ozonolysis of an alkene breaks the double bond and substitutes with compounds containing oxygen.

Given compounds that are formed are:

Propanal:  CH$_3$-CH$_2$-CH=O

Pentan-3-one: CH$_3$-CH$_2$-CO-CH$_2$-CH$_3$

So, the alkene is:

CH$_3$-CH$_2$-C=CH-CH$_2$-CH$_3$

               |

            CH$_2$-CH$_3$

IUPAC name

3-ethyl-hex-3-ene

Note

Please try to manage with the structure as it is bit difficult to draw here.