Question

(b) Prove that :
(sin 0- cosec 0) (cos 0- sec 0) (tan 0 + cot 0) = 1​

Answer 1

Step-by-step explanation:

(sin¢-cosec¢)=sin¢-1/sin¢=(sin^2¢-1) /sin¢=-cos^2¢/sin¢

similarly,(cos¢-sec¢)=-sin^2¢/cos¢

and (tan¢+cot¢)=(sin¢/cos¢+cos¢/sin¢)=(sin^2¢+cos^2¢)/sin¢.cos¢=1/sin¢.cos¢

putting these values in equation we get,

(-cos^¢/sin¢)×(-sin^2¢/cos¢)×(1/sin¢.cos¢)=1