(b)Prove that the perimeter of a triangle is greater than the sum of the lengths of the three altitude of the triangle.
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Answer:Prove that the perimeter of any triangle is greater than the sum of three altitudes. Given : ABC is a triangle in which AD, BE and CF are perpendiculars. Proof : Since in a right angled triangle, hypotenuse is the longest side. AB+BC+CA>AD+BE+CF Hence Proved.
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