Question

B= {r:r£A,3r is not a set of A}

Answer 1

Answer:

Mark as a brilliant please

Step-by-step explanation:

= {(a,b)∈ R× R: ∣a− 5∣< 1 and ∣b− 5∣< 1}

Now,

∣a−

5∣<

1⟹

a∈

(4,6)

and

∣b−

5∣<

1⟹

b∈

(4,6)

∴ A= {(a,b): a∈ (4,6),b∈ (4,6)}

Now, we have

B=

{(a,b)∈

R×

R:

4(a−

6)

2

+

9(b−

5)

2

≤

36}

Considering conditions from setA

, we can clearly see that they satisfy conditions in set B as maximum value of

4(a− 6)

2

+ 9(b− 5)

2

= 4(4− 6)

2

+ 9(6− 5)

2

= 16+ 9= 25≤ 36

Apart from these values of a and b

, we have

a=

6,b=

7

satisfying the equation and many more such values.

Hence,

A⊂

B

.