Question

ब्रैकेट टू एक्स स्क्वायर माइनस 5 बाय क्यूब ब्रैकेट क्लोज स्क्वेयर​

Answer 1

Answer:

$25y^{6}-20x^{2} y^{3}+4x^{4}$

Step-by-step explanation:

$(2x^{2}-5y^{3})^{2}\\(-5y^{3}+2x^{2})^{2}\\(-5y^{3}+2x^{2})(-5y^{3}+2x^{2})\\-5(-5y^{3}+2x^{2})*y^{3}+2(-5y^{3}+2x^{2})*x^{2} \\25y^{6}-10x^{2} y^{3}+2(-5y^{3}+2x^{2})*x^{2} \\25y^{6}-10x^{2} y^{3}-10x^{2} y^{3}+4x^{4}\\25y^{6}-20x^{2} y^{3}+4x^{4}$

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