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A ladder rests against a vertical wall such that the top of the ladder reaches the top of the wall. The ladder is inclined at 60° with the ground, and the bottom of the ladder is 1.5m away from the foot of the wall. Find
(i) the length of the ladder, and (ii) the height of the wall.
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Let PQ is a wall of height h.
Let QR is ladder and QR = 1.5 m.
Since ladder makes an angle 60° with the ground
i.e., ∠PRQ = 60°
From right angled ΔPQR
tan 60° = PQ/QR
⇒ √3 = h/1.5
h = 1.5 × √3
= 1.5 × 1.732 [∵ √3 = 1.732]
= 2.598 m
= 2.60 m
Hence, height of wall = 2.60 m
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