Math, asked by abhijithajare1234, 21 days ago

༒ Bʀᴀɪɴʟʏ Sᴛᴀʀs
༒Mᴏᴅᴇʀᴀᴛᴇʀs
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Answered by kamalhajare543
8

Answer:

your answer is given in attachment

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Answered by PinkVine
0

Solution

: lim x-1

√√√2sin ¹x

X

To evaluate this limit,

Put x = 1 - y so thay y → 0

2sin ¹(1-y) √1-(1-y) lim

= lim

2sin ¹(1-y)

If we directly Substitute y = 0, then

√√√2sin ¹(1-0)

√√√2sin ¹1 0

T 2

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