Question

༒ Bʀᴀɪɴʟʏ Sᴛᴀʀs,

༒Mᴏᴅᴇʀᴀᴛᴇʀs

༒Other best user

Solve it.
No spam​

Answer 1

Step-by-step explanation:

L.Hosp :

0 - √2 . 1 / 2 √ sin-¹x × 1 / √ 1 - x²

√2 - 1√ π/2 . 1 / √ 1+1 = √2/π

The correct answer is √2/π

$hope \: it \: helps \: you$

Answer 2

▬▬▬ஜ۩۞۩ஜ▬▬▬▬

✶⊶⊷⊶⊷❍ ❥ ❍⊶⊷⊶⊷✶

$\huge\color{cyan}\boxed{\colorbox{black}{Solution❤}}$

$= lim \: x - > \: 1 - \frac{( \sqrt{\pi} - \sqrt{ {2 \: sin}^{ - 1} } x) \: }{ \sqrt{1 - x} } \times\frac{( \sqrt{\pi} + \sqrt{ {2 \: sin}^{ - 1} } \times \: x) \: }{( \sqrt{\pi} + \sqrt{ {2 \: sin}^{ - 1} } \times \: x) \:} \\ \\ = > (rationalize \: the \: denominator \: ) = > \\ \\ = > lim \: x - > \: 1 - \frac{2( \frac{\pi}{2} - {sin}^{ - 1 \: x} }{ \sqrt{1 - x} } ( \sqrt{\pi} + \sqrt{2 {sin}^{ - 1} } x) \\ \\ = > lim \: x - > 1 \frac{2 \cos( - 1) x}{ \sqrt{1 - x} } \times \frac{1}{2 \sqrt{\pi} } \\ \\ now \: we \: will \: put \: the \\ value \: of \: x \: as \: \cos(?) \\ \\ we \: get \: \\ \\ lim \: - > \: 1 - \frac{2}{ \sqrt{2 \sin( { \frac{?}{2} }^{2 \sqrt{\pi} } ) } } \\ \\ = \sqrt{ \frac{2}{\pi} }$

✶⊶⊷⊶⊷❍ ❥ ❍⊶⊷⊶⊷✶

▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬