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༒ Bʀᴀɪɴʟʏ Sᴛᴀʀs

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$\huge{\underline{\mathtt{\red{Q}\pink{U}\green{E}\blue{S}\purple{T}\orange{I}\red{0}\pink{N}}}}$

$\begin{gathered}\sf{if \: a \: b \: c \: and \: d \: are \: in \: proportion \: prove \: that} \\ \sf{abcd( \: \frac{1}{a}^{2} +\frac{1}{b}^{2}\frac{1}{c}^{2} \: \frac{1}{d}^{2})= {a}^{2} {b}^{2} {c}^{2}}\end{gathered}$

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Answer 1

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$\huge{\underline{\mathtt{\red{Q}\pink{U}\green{E}\blue{S}\purple{T}\orange{I}\red{0}\pink{N}}}}$

$\begin{gathered}\sf{if \: a \: b \: c \: and \: d \: are \: in \: proportion \: prove \: that} \\ \sf{abcd( \: \frac{1}{a}^{2} +\frac{1}{b}^{2}\frac{1}{c}^{2} \: \frac{1}{d}^{2})= {a}^{2} {b}^{2} {c}^{2}}\end{gathered}$