Question

༒ Bʀᴀɪɴʟʏ Sᴛᴀʀs

༒Mᴏᴅᴇʀᴀᴛᴇʀs

༒Other best user

$\sin\alpha + \beta + \sin (\alpha + 2 \beta ) + ... \sin(a + (n - 1) \beta ) = \\ \frac{ \sin( \frac{n \beta }{2} ) }{ \sin( \frac{ \beta }{2} ) }$
solve it
Class- 11
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Answer 1

Answer:

༒ Bʀᴀɪɴʟʏ Sᴛᴀʀs

༒Mᴏᴅᴇʀᴀᴛᴇʀs

༒Other best user

\begin{gathered} \sin\alpha + \beta + \sin (\alpha + 2 \beta ) + ... \sin(a + (n - 1) \beta ) = \\ \frac{ \sin( \frac{n \beta }{2} ) }{ \sin( \frac{ \beta }{2} ) } \end{gathered}sinα+β+sin(α+2β)+...sin(a+(n−1)β)=sin(2β)sin(2nβ)

solve it

Class- 11

Step-by-step explanation:

a=43

b=32

n=66