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The length and breadth of a rectangular sheet of paper are 60 cm and 30 cm, respectively. A square of side 5 cm is cut and removed from the four corners of the sheet. The rest of the paper is folded to form a cuboid (without the top face). Find the volume of the cuboid so formed (in cm³).
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Answer 1

$\large\underline{\sf{Solution-}}$

Given that,

The length and breadth of a rectangular sheet of paper are 60 cm and 30 cm, respectively.

A square of side 5 cm is cut and removed from the four corners of the sheet.

The rest of the paper is folded to form a cuboid.

So, it means

↝ Length of cuboid, l = 60 - 2 × 5 = 60 - 10 = 50 cm

↝ Breadth of Cuboid, b = 30 - 10 = 20 cm

↝ Height of cuboid, h = 5 cm

[ See the attachment ]

So, Volume of cuboid thus formed is

$\rm :\longmapsto\:\boxed{ \tt{ \: Volume_{Cuboid} = l \times b \times h \: }}$

So, on substituting the values of l, b and h, we get

$\rm :\longmapsto\:Volume_{Cuboid} = 50 \times 20 \times 5$

$\rm :\longmapsto\:Volume_{Cuboid} = 5000 \: {cm}^{3}$

Hence,

$\red{\rm :\longmapsto\:\boxed{ \tt{ \: Volume_{Cuboid} = 5000 \: {cm}^{3} \: }}}$

More to know :-

Formula's of Cube :-

Total Surface Area = 6(side)²

Curved Surface Area = 4(side)²

Volume of Cube = (side)³

Diagonal of a cube = √3(side)

Perimeter of cube = 12 x side

Formula's of Cuboid

Total Surface area = 2 (Length x Breadth + breadth x height + Length x height)

Curved Surface area = 2 height(length + breadth)

Volume of the cuboid = (length × breadth × height)

lDiagonal of the cuboid =√(l² + b² + h²)

Perimeter of cuboid = 4 (length + breadth + height)

Answer 2

Answer:

$\pink {\frak{ur \: answer}}$

Step-by-step explanation:

Volume of the cuboid formed=(50−2×5)×(30−2×5)×5(50-2×5)×(30-2×5)×5

=40×20×5=40×20×5

=4000cm3=4000cm3

Let the edge of the cube be x cm.

∴ The volume of the cube=x3∴ The volume of the cube=x3

Given, 4x3=40004x3=4000

⇒x3=1000⇒x3=1000

⇒x=10cm⇒x=10cm

∴ The edge of the cube whose volume is equal to the cuboid formed = 10 cm

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