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The length and breadth of a rectangular sheet of paper are 60 cm and 30 cm, respectively. A square of side 5 cm is cut and removed from the four corners of the sheet. The rest of the paper is folded to form a cuboid (without the top face). Find the volume of the cuboid so formed (in cm³).
Answers
Given :
Length of rectangular sheet of paper = 60 cm
Breadth of rectangular sheet of paper = 30 cm
Side of smaller square that is to cut = 5cm
To find :
Volume of the cuboid formed (in cm³).
Solution :
Length = 60 cm
New length = 60 - (5+5) cm = (60 - 10) cm = 50 cm
Breadth = 30 cm
New breadth = 30 - (5+5) cm = (30-10)cm = 20cm
[ Since,square is cut from each corner
5 cm will be cut from each side 5+5 ]
Length = 50cm
Breadth = 30cm
Height = 5 cm
[ for taking these as cuboid dimensions refer above attachment ] :⟶ This will give you a better view of the situation.
:⟶Volume = 50cm×30cm×5cm
:⟶Volume = 7500 cm³
➨ Length of rectangular sheet of paper = 60 cm
➨ Breadth of rectangular sheet of paper = 30 cm
➨ Side of smaller square that is to cut = 5cm
Volume of the cuboid formed (in cm³).
➨ Length = 60 cm
➨ New length = 60 - (5+5) cm = (60 - 10) cm = 50 cm
➨ Breadth = 30 cm
➨ New breadth = 30 - (5+5) cm = (30-10)cm = 20cm
[ Since,square is cut from each corner 5 cm will be cut from each side 5+5 ]
➨ Length = 50cm
➨ Breadth = 30cm
➨ Height = 5 cm
[ for taking these as cuboid dimensions refer above attachment ] :⟶ This will give you a better view of the situation.
volume of cuboid = Length×Breadth×Height
:⟶Volume = 50cm×30cm×5cm
:⟶Volume = 7500 cm³
➨ Volume of cuboid formed is
➨7500cm³.