Question

b) S= t3 - 4t2 + 3t. Find Vinst at t=2s and ains at t=3s.

Answer 1

Answer:12th

Maths

Continuity and Differentiability

Second Order Derivatives

If S = t^3 - 4t^2 - 5t Find...

MATHS

If S=t  

3

−4t  

2

−5t  

Find velocity & acceleration at t=2

EASY

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ANSWER

s=t  

3

−4t  

2

−5t

v=  

dt

ds

​  

=3t  

2

−8t−5

v∣  

t=2

​  

=3(2)  

2

−8(2)−5

=12−16−5=−9 m/s

a=  dt  square

 

d square  s

​  

=6t−8

9t=2

​  

=6(2)−8=4m/s  square

 

∴ Velocity at t=2s=9m/s (opposite to direction motion)

acceleration at t=2s=4m/s  square

 (in direction of motion)